Assignment #5 - 88B
Assignment #5 - 88B
T.A. HARRIS PARASKEVAS
DUE: NOV 12
WEIGHT: 25
Assignment 5
CABLE CAR VELOCITY
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THIS PROBLEM INVOLVES A 1000-FOOT CABLE THAT IS STRETCHED BETWEEN TWO
TOWERS WITH A SUPPORTING TOWER MIDWAY BETWEEN THE TWO END TOWERS. THE
VELOCITY OF THE CABLE CAR DEPENDS ON ITS POSITION ON THE CABLE. WHEN
THE CABLE CAR IS WITHIN 30 FEET OF A TOWER, ITS VELOCITY IS:
VELOCITY = 2.425 + 0.00175*D*D FT/SEC
WHERE D IS THE DISTANCE IN FEET FROM THE CABLE CAR TO THE NEAREST
TOWER. IF THE CABLE CAR IS NOT WITHIN 30 FEET OF A TOWER, ITS
VELOCITY IS:
VELOCITY = 0.625 + 0.12*D - 0.00025*D*D FT/SEC
PRINT THE TABLE STARTING WITH THE CABLE CAR AT THE FIRST TOWER
AND MOVING TO THE LAST TOWER IN INCREMENTS OF 10 FEET. AT EACH
INCREMENT OF 10 FEET, PRINT THE NUMBER OF THE NEAREST TOWER
(1 = FIRST, 2 = SECOND, 3 = END), THE DISTANCE FROM THE FIRST
TOWER, AND THE VELOCITY OF THE CABLE CAR.