Agatha Haddock (112233445)
COMP-202A, Section 0 (Fall 2010)
Instructor: Cuthbert Calculus
Assignment 1, Question 3 (c)


Order of evaluation for (((q*12-(4*(z/x)+100)*y-z)%5)/2+283)
For x = 4, y = 6, z = 11

q = 7.0

1. the / in 'z/x'					                              = 2
2. the * in '4*(z/x)'					                          = 8
3. the + in '4*(z/x)+100'			                        	= 108
4. the * in 'q*12'				                            	= 84.0
5. the second * in '(4*(z/x)+100)*y'	                	= 648
6. the - in 'q*12-(4*(z/x)+100)*y'	                   	= -564.0
7. the second - in  'q*12-(4*(z/x)+100)*y-z'	         	= -575.0
8. the %					                                	    = 0.0
9. the / in '((q*12-(4*(z/x)+100)*y-z)%5)/2'	         	= 0.0
10. the + 238 in '((q*12-(4*(z/x)+100)*y-z)%5)/2+283'  	= 283.0


NOTE: this is the order of evaluation taught in class. Java actually uses a 
slightly different order that is *equivalent*. The real Java evaluation order
for this expression is shown is Mathieu's solution.